2022-2023英语周报九年级第37期答案

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12.选D对于A,取CD中点F,连接MF,BF,则MF∥A1D且MF=3A1D,FB∥ED且FB=ED,由MF∥A1D与FB∥ED,A1D∩ED=D,MF∩FB=F,可得平面MBF∥平面A1DE,∴总有BM∥平面A1DE,故A正确;对于B,在矩形ABCD中,AB=2AD=2,E为AB的中点,得ED2=12+12=2=CE2,CD2=22=4所以CE2+ED2=CD2,∠CED=90°,∴,CE⊥ED,MF∥A1D,且MF2A1D,FB∥ED,FB=ED∠A1DE=∠A1ED=∠MFB=45°,由余弦定理,得MB=√BF+MF=2BF· MFcs∠MFB=,故B正确;对于C,因为M为A1C的中点,所以VA-DEM=VA.-CDE,设点A1到平面ABCD的距离为h,所以VA=EM=1A-CDE×S△ CDE Xh=-××言×1×2×h当平面A1DE⊥平面ABCD时,三棱锥A1-DEM的体积取得最大值,且hmax=y2,所以三棱锥A1DEM的积最大值为×=1,故C正确;对于D,若平A1DE⊥平面A1CD,则EA1⊥A1C,∵EA1=1,EC√2,则A1C=1,此时点A1在平面ABCD上,故不存某个位置,使得平面A1DE⊥平面A1CD,故错误选D

2021-2022英语周报九年级第37期答案

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