2022英语周报白色試卷 答案

第三部分写作第一节【写作指导】审题本题属于应用文写作中的邀请信立意写作时使用第一人称和第二人称,时态以一般将来时为主首段陈述写邮件的目的;中间段介绍讲座的写作时间、地点和内容,并说明邀请理由;最后思路几谋篇一段表达期待布局冂注意:考生也可以灵活安排每段的写作内容,但不可以遗漏要点推荐根据构思好的提纲确定写作可能用到的表达,表达to: invite, attend a lecture, waste food, raiseone' s awareness of等【佳作展台】Dear MikeI am writing to invite you to attend a lecture about Clear Your plateThe lecture is to be held in our school hall at 2: 30 pm nextThursday. It will be given by our headmaster, who will tell us the reasonsfor launching the campaign. Besides, he will talk about various activitiesto be carried out which are aimed at raising students awarenessof savingI think the lecture can help us have a better understanding of the campaignand form the habit of saving.i do hope you can join me. Please write back soonYours.Li hua亮点梳理】本文开篇点明写邮件的目的,接着详细介绍了此次讲座的相关情况,最后表达期望,内容完整,语勺流畅,同时使用了亮点词汇和句子。亮点词汇:atnd, launch, carry out, be aimed at, raIse one'sawareness of, have a better understanding of =o亮点句式:①非限制性定语从句 who will tell us the reasons forlaunching the campaign②强调句 i do hope you can join me

解:(1)f(x)=e-4x-2的定义域为R,f(x)=e2-4,(1分)令f(x)<0,得x 0,得x>hn4,所以函数∫(x)在区间(-∞,2n2)上单调递减,在区间(2ln2,+∞)上单调递增所以函数f(x)在区间[0,2lm2]上单调递减,在区间[2m2,3]上单调递增.(2分)又f(0)=-1、f(3)=e-14,显然f(3)>f(0),(3分所以f(x)m=e3-14、f(x)m=f(2ln2)=2-8ln2.(4分(2)因为f(x)+x2-k≥0对任意x∈R恒成立所以e-4x-2+x2-k≥0对任意x∈R恒成立所以k≤e2+x2-4x-2对任意x∈R恒成立.(5分)令h(x)=e2+x2-4x-2,则h'(x)=e2+2x-4由于h"(x)=e+2>0,所以h(x)在R上单调递增.(6分)又(1)=6-2>0,(4)=e-12<0《所以存在唯一的x∈(4,1),使得h(x)=0,且当x∈(-∞,x)时,h(x)<0;当x∈(x,+)时,h(xn)>0.(7分)故h(x)在(-∞,x0)上单调递减,在(x0,+∞)上单调递增所以h(x)==h(x)=e0+x2-4x-2.(8分)又h'(x0)=0,即e0+2x0-4=0,所以e0=4-2x0所以h(x0)=e0+x2-4x0-2=4-2x0+x2-4x0-2=x2-6x0+2=(x0-3)2因为x∈(,1),所以h(x0)(。54),(10分)又因为k≤e+x2-4x-2对任意x∈R恒成立,所以k≤h(x0)又k∈Z,所以km=-3.(12分)

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