英语周报答案高二牛津期末复习46

67. One possible versionIn his diary, the man mentioned he wished to sink to the ocean with his wife but fortheir daughter he had to live. Without him, their baby daughter would become an orphan.After drowning himself in sorrow for a short time, he uplifted himself and learned how toraise his baby. Whenever faced with hardships, he would inspire himself with his wifewords-"Take care of our child. " Seeing the little girl grow into a sunny, pretty girl withdouble love from both parents, the man knew he made it to keep his promise.The story was finished and the class was silent. Nobody talked or laughed as usualInstead, it seemed that every student was lost in deep thought, tasting the moving life story.The teacher was sure that the students were reflecting on their replies and that they hadunderstood the moral of the story. Of the Good and Evil in this world, there are hiddensecrets behind them. So we should not really focus on the surface and judge anyone withoutunderstanding them first. Put yourself in others' shoes and then you can really understandtheir behavior

31.(10分,每空2分)(1)初级卵母细胞(2)MI姐妹染色单体分开,MⅡ同源染色体分离25(3)①得到的F1中,仅灰身雄果蝇的染色体形态正常,其余均为含异常染色体的个体,因此可通过后代的表型对染色体情况加以区分⑦3【解析】(1)由图1可知,通过减数分裂形成的子代细胞体积大小不一,可判斷图1为卵細胞的形成过程,因此胞②为初缀卵母细胞(2)常规减数分裂是减数第一次分裂同源染色体分离,减数第二次分裂着丝粒分裂,姐妹染色单体分开,而从图1可知,在“逆反”减彀分裂中,减数第一次分裂是着丝粒分裂,姐妹染色单体分开,而减数第二次分裂是同源染色体分离,正如所谓的“逆反”,MⅢⅡ中的细胞出现了染色体不均分,那么这个细胞形成的配子均异常,因此若MⅢ中约25%的细胞出现了染色体不均分的情况,那么可以估算出约25%的配子异常(3)①染色体结构变异可在光学呈微镜下观察到,分析图2可知,果蝇甲和果蝇乙的基因型分别为BOX"Y与bbXX,其杂交得到的F1中,仅灰身雄果蝇的染色体形态正常,其余均为含异常染色体的个体,可通过后代的表型对染色体情况加以区分。因此,筛选a可用光学显微镜观察染色体的形态选出果蝇甲,筛选b不用光学显微镜观察就能选出“含异常染色体个体”,②F1黑身雄果蝇的基因组成为bOXY,灰身雌果蝇的基因组成为BbXⅩ和ObXⅩ,为从F1中筛选出常染色体正常的雌果蝇,让F黑身雄果蝇分别与灰身雌果蝇杂交,把两对染色体分开考虑,则后代中黑身果蝇(bb或Ob且XX或XY)占1/2×1/2=1/4,灰身果蝇占1-1/4=3/4,即选定后代中灰身果蝇:黑身果蝇=3:1的杂交组合中的雌性亲本即为所需。

以上就是英语周报答案高二牛津期末复习46，更多英语周报答案请关注本网站。