2022七年级下册英语周报33期答案

21.【详解】(1)因为f(x)=单调递增,所以ax+x+1f(x)=eax'+(1-2a)x20对任意x∈[0,+∞)恒成立,即ax≥2a-1对任意ax+x+Ix∈[0.+∞)恒成立,∴2a-1≤0,即0 时,令∫(x)=0得x∴f(x)在03q-1上递减 0,又ax2+1a>0,所以a>1,设两根为x,x(x 0’所以F(x)2在(0,1)上递增,所以F(x) 2,所以G(x)>G(0)=2,即f(x)+f(x)>1+,综上:1+ 0时,e2>x2+x+1,所x2+x+12以()+/(x2)=-ee+e x+、eax+I ax,+l x,x1+x2x2+x+1+xx2+x2+12axr2(*+x2)+2x 2+x+x231+-xx=1+22

第三节One possibleversionParagraph 1He was determined to protect the flowers. So he built ahigh wall around them. Not feeling satisfied, he even setup rules as to who could enter the garden, how they mustenter,and what they must follow while they were there.Asa result, children were forbidden to enter and appreciatethe flowers as before. For his part, he continued to see to itthat his treasure received enough sunlight and water so thatthe flowers continued to perform their wonderful magicParagraph 2Hethe flowers seemed to fade day by day,so theman went everywhere for help. He visited every expert, onlyto find his efforts in vain. He felt on pins and needles, see-ing his beloved flowers dying. One evening, he was wan-dering on the street aimlessly when he suddenly noticed theflower woman on the same spot where he had met her, giving away her amazing flowers. It finally dawned on him thatthe flowers are gifts not passessions and that only by sharingcan the magic remain and last

以上就是2022七年级下册英语周报33期答案，更多英语周报答案请关注本网站。