英语周报高三第15答案

Thinking of thal, my face felt hot. To our amazement, Mrs. Ferguson replied, " You are welcometo plug it in here. When saying that, she pointed to the mirror in her room.That' s really nice ofyou."Alex and I said and walked into her room. When we were fixing our hair Mrs. Ferguson chattedwith us about our tryout for cheerleaders. We had a pleasant chat, during which I found MrsFerguson genuinely cared about her studentsParagraph 2:When we were to leave, Mrs. Ferguson said,"Can I watch your tryout? " Of course, MrsFerguson, we'd be honored, I replied, feeling amazed again. During the tryout, both Alex and Iperformed well and passed the test. Mrs. Ferguson sincerely congratulated us. Meanwhile, sheinded us to study hard when we tried to develop our personality by being cheerleaders. ThrouglFerguson, we'd be honored, " I replied, feeling amazed again. Duringperformed well and passed the test. Mrs. Ferguson sincerely congratulated us. Meanwhile, shereminded us to study hard when we tried to develop our personality by being cheerleaders. Througlthese and many other nice gestures, Mrs. Ferguson gradually gained love and support from all of usHow blessed we were to have another great teacher

18.(IG分)(1)C(2分)(2)减少钒的损失,据高阿收率(2分(3)Na:Ti2+(x-1)l1:)+2H-Ti)2·rH:O)+2Na”(2分)(1)①性(2分)②8.7(2分)(5)pl小于8时,随溶液pH增大,vO的水解度降低沉钒率升高;p大于8时,随p的增大NI与OH-结合,NHVO2(s)=NH《aq)+VO;(an)平衝右移,沉淀溶解(2分)(6)HVO为(2分)2HvV2O3+H2O(2分)【解析】木题以湿法回收sCR的工艺流程为载休,考了反应效率的控制,物质的循环利川、方程式的书5写,实验操作及p的相关计算1)"碱浸“时适当提高浸出温度、使川搅拌器、适当增大Na川H滓液浓度均可提高"戤浸”的浸出效率,增大固液北(sR:Na(川H溶液).在Na(川H溶液量相同时,增加因体的量,浸出效牛将会降低,(2)“水洗”∏的是洗掉过量的NaOH和生成的NaVO3·洗液”浓縮后与“浸出液”合井的口的是减少识的损尖,提高回收帛(3)由流P图可知,转化”是将№:TR转化为TO2·rH2O,根据元素守恒和电荷守可得反应的离予方程式为Na:T+(x-1)H:O+2H=T:rH (-+2Nn'(4)①MO1)3既存在碱式电离平衡又存在酸式电离平衡,依据电离常数可知,眠式电离程度大于酸式电离度,所以《OI1)水溶液显碱性②“沉“是将[A(),]转化为A(O1D)3,K,=c{[A])xc()=2.0×10"mo·1.2=10-·ml·L."xc(H·),r(l')=20×10-mol·1.1,则pl8.7·pl最大为8.75)vO,易水解使溶液显碱性p|小于8时,随溶液pl的增大.VO1的水解度减小当pl大于8时.随pH的增大.NH:与OH结合NHvO(s)NH;(aq)+v);(aq)平衡右移.沉淀溶解(6)n(LvO)=、231g=2ml,C点所得产物中,n(V)=2mo,l23131g-100kmnl'100恰好为IVv,的相对分子质量,从而得出C点产物为HvO,在D点,剩余因体质量为23g52g=182g此时V的质显为2ml×5lg·mols102g则含()的质鼠为182g-102g=80g,n(())=5mol.从而得出D点产物的化学式为16g·nolV1,反应的化学方程式为2HV.△y2+1:0

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