2022-英语周报七年级第四期答案

思路分析作者遇到车祸住进医院,在整理自己的东西时,发现其中有一件夹克是醉酒驾驶的肇事者的,作者在夹克的口袋里发现一个笔记本,里边夹着一张2万美元的中奖的刮刮卡。作者面临春一个选择:这张卡该自己留下还是归还给差点要了自己命的肇事者呢?审要求:读后续写,本文语篇类型属于记叙文。2审人称、时态:以第一、三人称以及一般过去时为主3审要点护士说明作者住院的原因并把物品交给作者一作者发现了肇事者的笔记本和中奖的刮利卡并产生思想斗争一作者从笔记本中了解到肇事者一直在努力戒酒一作者深知戒酒是件不易的事。4.续写时需要注意原文中以下线索i)hat caused the accident?2)How did the writer feel after finding the winning scratchticket? Why?3)What was written in the notebook? What impressed the writer?4)How did the story of the writer's father influence his decision?审所绐首句:Para. I Just as that thought entered my mind, the nurse walked in根据上一段最后一句可知作者不愿看到任何人遭受父亲我涸过程中所受的苦,哪怕是差点要了他的命的那个人。本段开头一句是正想着这个事,护土进来了。接下来作者应该会向护士说明自己发现了什么,自己怎么看待肇事者以及自己的决定是什么。Para. 2 The next couple of days passed, and it was time to goome and take care of myself问到家后发生了什么?作者的感受如何?这一段应交代文章的垂要线索—那张中奖刮刮卡的最终归属,以及作者的内心感受参考范文Just as that thought entered my mind, the nurse walked in. I saidto her, "I was going through this bag of my belongings when I foundthat this jacket belonged to the other person in the accident. "Shereplied, "Sorry, we must have made a mistake. " I told her about thejoumal, saying that he had gone without drinking for 75 days the daybefore he hit me. He was trying. Then I handed her the jacket and thnotebook, aiong with the winning 20, 000 scratch ticketThe next couple of days passed, and it was time to gotake care of myself. When I got to the gate, I checked the mail asusual. Unexpectedly, I found an envelope which included the winnings20, 000 scratch ticket and a note saying, "You retumed this to me ata time when most people would have kept it. This is for you. I'm ssorry for your pain resulting from my fault. I stood there cryingpraying for a successful ending to his recovery journey

16为第1同3分几图式各1分,第2问9分,①⑤①⑧⑩式各1分,⑥⑨式各2分分【解析】(1)由几何关系可知,带电粒子在磁场中做圆周运动的半径r=1洛伦兹力提供向心力:B0=之t2得:B=2my2)设场强沿x、y正方向的分量分别为E.E°对于先后经过f、h点的离子,由动能定理可得E, qlehI-4E-2EE对于先后经过(、g点的离子,由动能定理可得Ey|/g=4.5E4-1.5E由于|ehl=1g=3iefE,1可得:E故电场强度方向与x轴夹角为60°,指向右下方(3)该离子进入电场时速度与场强垂直,在电场中做类平抛运动,设加速度为a,从d点到再次穿过y轴,沿电场方向位移:5垂直于电场方向位移:s=vt且at解得故离子再次穿过y轴时,速度大小v=√v2+解得v=√13设速度方向与y轴负方向夹角为沿x、y方向的分速度分别为:v=-vsin60°+ atcos60°⑩03故m0=27设离子再次进入磁场运动时圆周运动半径为r1,By当离子经过x轴的坐标值最大时,圆心在x轴上如图所解得最大坐标x1=n1(1+c00)解得参考:第1问3分,①②③式各1分;第2问3分,①⑤⑥式各1分;第3问12分,⑦~0式各1分,+√13

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