2022－2022高二英语周报28期答案

第二节书面表达【写作思路】根据试题要求,考生需要写一篇记叙文,记述身边一位值得尊敬和爱戴的人。首先考生需要介绍自己最尊敬和爱戴的人是谁,简单地介绍一下他(她)。然后,陈述为什么他(她)值得尊敬和爱戴。最后,可以对前文进行一个总结,使文章结构严谨。本文的写作重点在"尊敬和爱戴的原因",考生可围绕这个要点适当拓展,从性格特点、处事风格等方面展开写作。【范文赏读】The most beloved and respected person around me is my teacher, Ms LiThough she has been teaching English for twenty years, she is still passionateabout teaching. She is kind and considerate towards us just like our dear motherWe all respect her because she always tries new ways to make her classes livelyand interesting. Hardworking and knowledgeable, she is one of the best teachersin our school. When we have a problem, we will turn to her for help. She alwaystalks to us patiently and helps us to find a solution. In our eyes, she is not onlyour teacher, but also our best friend. Those are why she deserves our respect【亮点词句】亮点词汇: beloved, respected, be passionate about, be consideratetowards, turn to sb. for help, in one's eyes亮点句式:Why引导的表语从句( why she deserves our respect)

19.【考查目标】必备知识:本题主要考查空间中点、线、面位置关系直三祾柱的性质等知识.关键能力:通过几何体体积的求解和线线垂直的证明考查逻辑思维能力、运算求解能力、空间想象能力.学科素养:理性思维、数学应用、数学探索【解题思路】(1)取BC的中点M,连接EM,由三角形中位线性质结合BF⊥A1B1推出BF⊥EM,进而推出EM⊥平面BCF,将求三棱锥F-EBC的体积转化为求三棱锥E-FBC的体积,再利用三棱锥的体积公式求解即可;(2)要证明线线垂直只需证明其中一条直线垂直于另一条直线所在的平面,连接A1E,B1M,证明BF⊥平面EMB1A1即可证得结果解:(1)如图,取BC的中点为M,连接EM由已知可得EM∥AB,AB=BC=2,CF=1,EM=AB=1,AB∥A1B1,由BF⊥A1B1得EM⊥BF又EM⊥CF,BF∩CF=F所以EM⊥平面BCF,故V三棱锥FEBC=V三E-FBC=CFxEMExxxI=(2)连接A1E,B1M,由(1)知EM∥A1B1,所以ED在平面EMB1A1内在正方形CC1B1B中,由于F,M分别是C1,BC的中点,所以由平面几何知识可得BF⊥B1M,又BF⊥A1B1,B1M∩AB1=B1,所以BF⊥平面EMB1A1,又DEC平面EMB1A1,所以BF⊥DE【规律总结】(1)三棱锥体积计算一般都要用等体积法,本题通过转换三棱锥的顶点将求解三棱锥F-EBC的体积转化为求解三棱锥E-FBC的体积.(2)证明线线垂直的思路:可通过证明其中一条直线垂直于另一条直线所在的平面,即证线面垂直,要证明线面垂直可通过证明直线与平面内的两条相交直线垂直

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